Answer:
Option A
Step-by-step explanation:
To know the correct answer to the question, let us write an equation illustrating the formation of MgBr₂.
This is illustrated below:
1. Magnesium (Mg) is divalent element hence it will lose 2 electrons to form magnesium ion (Mg²⁺) as shown below
Mg —> Mg²⁺ + 2e¯
2. Bromine (Br) is a univalent element. Two bromine atom will receive the two electrons (i.e each atom receives 1 electron) to form the bromide ion (Br¯) as shown below:
2Br + 2e¯ —> 2Br¯
Combine both equation
Mg + 2Br + 2e¯—> Mg²⁺ + 2e¯ + 2Br¯
Cancel out 2e¯
Mg + 2Br —> Mg²⁺ + 2Br¯
Thus we have
Br—Mg—Br
From the illustration made above, we can see that two bromine atom is receiving 1 electron each from the magnesium atom