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What angle (in degrees) is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-seventh of its initial value
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What angle (in degrees) is needed between the direction of polarized light and the axis of a polarizing filter to cut its intensity to one-seventh of its initial value

User Scott Joudry
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1 Answer

11 votes

Answer:

I = I0 cos^2 θ

cos^2 θ = I / I0 = 1/7

cos θ = (1 / 7)^1/2 = .378

θ = 67.8 deg

User MahaSwetha
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5.1k points
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