Question

A Coolie raises a box of mass 20 kg to a height of 1.5m. If the force of gravity on 1 kg is 10N. The work done by the Coolie is​

Answer 1

Solution:
Mass(m)=20kg
Displacement (s)=1.5m
For 1 kg force of gravity=10N
We have,
F=mg
or,10=1xg
or g=10m/s^2
Then,
Total work done by the coolie(W)=force x displacement
or,W=mxgxs
=20x10x1.5
=300J