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Find the distance between the two points in simplest radical form.
(0, –4) and (-3,-1)

Find the distance between the two points in simplest radical form. (0, –4) and (-3,-1)-example-1

2 Answers

5 votes

Explanation:

Hey there!

Given;

The points are;(0,-4) and (-3,-1).

Use formula for distance between the two points.


d = \sqrt{ {(x2 - x1)}^(2) + {(y2 - y1)}^(2) }

Put all values.


d = \sqrt{( { - 3 - 0)}^(2) + ( { - 1 + 4)}^(2) }

Simplify to get answer.


d = √(9 + 9)


d = √(18)


d = 3 √(2)

Therefore, the distance is 3(2) units or 4.24 units.

Hope it helps...

User Jinsungy
by
4.9k points
3 votes

Answer:

3
√(2)

Explanation:

Calculate the distance d using the distance formula

d =
\sqrt{(x_(2)-x_(1))^2+(y_(2)-y_(1))^2 }

with (x₁, y₁ ) = (0, - 4) and (x₂, y₂ ) = (- 3, - 1)

d =
√((-3-0)^2+(-1+4)^2)

=
√((-3)^2+3^2)

=
√(9+9)

=
√(18)

=
√(9(2))

=
√(9) ×
√(2) = 3
√(2)

User Ugy
by
5.4k points