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5 votes
ivy bought 10 packs of cups for her holiday party. a pack of medium cups costs $1.80 and a pack of large cups costs $2.40. she paid a total of $21.60. how many packs of each size cup did she buy?

User Gubbel
by
5.8k points

2 Answers

5 votes

Answer:

4 packs of medium cups and 6 packs of large cups

Explanation:

1.80x + 2.40y = 21.60

1.80(4) + 2.40(6) = 21.60

7.2 + 14.4 = 21.60

21.60 = 21.60

User Greg Robertson
by
5.5k points
3 votes

Answer:

Ivy bought 4 packs of medium cups, and 6 packs of large cups.

Explanation:

To solve this problem, we will have to use a system of equations. Our first equation will represent the cups, and our second equation the costs.

Let
m equal medium cups.

Let
l equal large cups.


m+l=10


1.80m+2.40l=21.60

Let's use substitution to solve this system.

Subtract
l from both sides of the first equation:


m=10-l

Let's substitute
10-l into the second equation for
m:


1.80(10-l)+2.40l=21.60

Distribute
1.80 into
(10-l):


18-1.80l+2.40l=21.60

Combine like terms:


18+0.6l=21.60

Subtract
18 from both sides of the equation:


-0.6l=3.60

Divide by the coefficient of
l, which is
0.6:


l=6

Ivy bought 6 packs of large cups.

_

Let's substitute
6 into the first equation to find the number of medium cup packs:


m+6=10

Subtract
6 from both sides of the equation:


m=4

Ivy bought 4 packs of medium cups.

_

We can check our work 2 ways; by substituting our solved values into the initial equations.

1st Equation Check:


(4)+(6)=10


10=10

2nd Equation Check:


1.80(4)+2.40(6)=21.60


7.2+14.4=21.60


21.60=21.60

Our answers are correct!

User David Snowsill
by
5.2k points
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