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What is the enthalpy of reaction for the decomposition of calcium carbonate?

CaCO3(s) Right arrow. CaO(s) + CO2(g)

User Nzingha
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2 Answers

2 votes

Answer:

Step-by-step explanation:

You will need to look up the Standard Heats of Formation* for each substance and apply Hess's Law Equation.

ΔH⁰(rxn) = ∑ΔH⁰(Products) - ∑ΔH⁰(Reactants)

*Std Heats of Formation can be found in the appendix of most college chem texts.

For this problem:

Given CaCO₃(s) => CaO(s) + CO₂(g)

∑ΔH⁰: -635.1 Kj/mole -393.5Kj/mole -1206.9

ΔH⁰(rxn) = [(-393.5 Kj/mole) + (-393.5Kj/mole)] - (-1206.9Kj/mole)

= (-635.1 -393.5 + 1206.9) Kj/mole

= +178.3 Kj/mole

User Timothy Macharia
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2 votes

Answer:

656.3 kJ

This reaction is endothermic

Step-by-step explanation:

edge 2020

User Daniel Paull
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5.7k points