Question

Find the value of z such that

0.6826 of the area lies between
– z and z. Round your answer to two decimal places.

Answer 1

z = 1.00

Step-by-step explanation:

Given:

Probability of z value = 0.6826

By using standard normal table for z value.

P(-z < Z < z) = 0.6826

P(Z < z) - P(Z < -z) = 0.6826

We know that

P(Z < z) + P(Z < -z) = 1

So,

2P(Z < z) - 1 = 0.6826

2P(Z < z) = 1 + 0.6826

2P(Z < z) = 1.6826

P(Z < z) = 1.6826 / 2

P(Z < z) = 0.8413

So,

P(Z < 1.00) = 0.8413

z = 1.00