Question

A student measured the mass of some sodium chloride for a lab. the lab called for 6.25 g (the accurate measurement ) , but the student measured 6.00 g instead . what is the percent error for this mass ? Show your work .

Answer 1

The answer is

`\huge 4\%`

Step-by-step explanation:

The percentage error of a certain measurement can be found by using the formula

`P(\%) = (error)/(actual \: \: number) * 100\% \\`

From the question

actual mass = 6.25 g

error = 6.25 - 6 = 0.25

So we have

`p(\%) = (0.25)/(6.25) * 100`

We have the final answer as

4 %

Hope this helps you