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The first aircraft has 89 more seats than the second aircraft. The third aircraft has 45 fewer seats than the second aircraft. If their total number of seats is 401, find the number of seats for each aircraft

User Jigarzon
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1 Answer

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Answer: The first aircraft has 208 seats.

The second aircraft has 119 and the third has 74.

Explanation:

The equation is x+89 + x + x-45 = 401

combine terms: 3x + 44 = 401 Subtract 44 from both sides 3x=357

divide both sides by 3

x= 119

substitute x in each term of the equation to find the number of seats on each aircraft

119 + 89 = 208 for #1 x= 119 for #2 119- 45= 74 for #3

User David Chan
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