Question

6. A child tugs on a rope attached to a 0.62-kg toy with a horizontal force

of 16.3 N. A puppy pulls the toy in the opposite direction with a force 15.8
N.What is the acceleration of the toy? (Hint: Remember direction:
towards child or puppy?)

Answer 1

Step-by-step explanation:

Force Mass * acceleration

F = ma

a = F/m

Sum of force = 16.3N - 15.8N = 0.5N

Mass = 0.62kg

Substitute

a = 0.5/ * 0.62

a = 0.81m/s²

The acceleration of the toy is 0.81m/s²