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A girl tries to jump over a 0.825 m

wide creek by jumping at 3.87 m/s
at a 18.8° angle. What is her
height when she reaches the
other side of the creek?

A girl tries to jump over a 0.825 m wide creek by jumping at 3.87 m/s at a 18.8° angle-example-1
User Hemal
by
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1 Answer

3 votes
3.87 m/s)*sin (18.8 degree) = 1.247 m/s. That’s the vertical component of her initial velocity. The horizontal component is 3.864 m/s. It takes(0.825m/s)= 0.225 seconds for her to cross the creek. Height = 0.0325 meters
User Apalabrados
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5.6k points