Question

What is the Theoretical yeild of CaCO3 from 2 g of CaCl2 and 2.5 g of K2CO3

Answer 1

Theoretical yield of CaCO₃ is 2.002 g.

Step-by-step explanation:

Given data:

Mass of K₂CO₃ = 2.5 g

Mass of CaCl₂ = 2 g

Theoretical yield of CaCO₃ = ?

Solution:

Chemical equation:

K₂CO₃ + CaCl₂ → CaCO₃ + 2KCl

Number of moles of K₂CO₃:

Number of moles = mass/molar mass

Number of moles = 2.5 g/ 138.205 g/mol

Number of moles = 0.02 mol

Number of moles of CaCl₂:

Number of moles = mass/molar mass

Number of moles = 2 g/ 110.98 g/mol

Number of moles = 0.02 mol

Now we will compare the moles of CaCO₃ with K₂CO₃ and CaCl₂.

CaCl₂ : CaCO₃

1 : 1

0.02 : 0.02

K₂CO₃ : CaCO₃

1 : 1

0.02 : 0.02

Theoretical yield of CaCO₃:

Mass = number of moles × molar mass

Mass = 0.02 mol × 100.1 g/mol

Mass = 2.002 g

Theoretical yield of CaCO₃ is 2.002 g.