29.0k views
5 votes
Given \sqrt{27}+\sqrt{108}

27

+
108


=27^{\frac{1}{2}}+108^{\frac{1}{2}}=27
2
1


+108
2
1




3^{\frac{1}{2}}\cdot9^{\frac{1}{2}}+3^{\frac{1}{2}}\cdot36^{\frac{1}{2}}3
2
1


⋅9
2
1


+3
2
1


⋅36
2
1



3\cdot3^{\frac{1}{2}}+6\cdot3^{\frac{1}{2}}3⋅3
2
1


+6⋅3
2
1



18\cdot3^{\frac{1}{2}}18⋅3
2
1


User Mello
by
5.4k points

1 Answer

6 votes

Answer: I need points sorry that I'm to dumb to answer.

Explanation:

User Mauker
by
5.3k points
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