270,755 views
2 votes
2 votes
Here is a set of data

Here is a set of data-example-1
User Roy Paterson
by
2.4k points

2 Answers

12 votes
12 votes

Answer:

a) 1.8

b) 11.8

c) 23.6

a)

(2.4 + 1.6 + 3.2 + 0.3 + 1.5) / 5 = 1.8

b)

(12.4 + 11.6 + 13.2 + 10.3 + 11.5) = 11.8

c)

(24.8 + 23.2 + 26.4 + 20.6 + 23) / 5 = 23.6

or,

11.8 × 2 = 23.6

User Otheus
by
2.8k points
26 votes
26 votes

Answer+Step-by-step explanation:

a)

original mean = (2.4+1.6+3.2+0.3+1.5)÷5

= 9÷5

= 1.8

b)

New mean = ((2.4+10)+(1.6+10)+(3.2+10)+(0.3+10)+(1.5+10))÷5

= (12.4) + (11.6) + (13.2) + (10.3) + (11.5)) ÷ 5

= 59÷5

= 11.8

Note:

11.8-10 = 1.8

then

New mean = original mean + 10

c)

Newest mean = ((2×12.4)+(2×11.6)+(2×13.2)+(2×10.3)+(2×11.5))÷5

= ((24.8)+(23.2)+(26.4)+(20.6)+(23))÷5

= 118÷5

=23.6

Note :

Newest mean = 2×(New mean)

= 2×(original mean + 10)

User Mike Williams
by
2.9k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.