The given statement can be written as:
6+√-80
To solve √-80 re-write -80 as -1 * 80
Now √-80 =√-1 * 80
Now we can write it as:
6+ √-1 * √80
We know that √-1 = i
Thus it becomes:
6+ i√80
Now find the square root of 80
80 does not have a perfect square root
Its square root can be found as 80 = 4*4*5
Then,
6+i√4*4*5
Notice that 4 makes a pair.. So we will write it outside the square root
6+1*4√5
We will write it as:
6+4i√5
Thus the correct option is 6 plus 4 i times the square root of 5....