Question

A sample of 4.0 mol of neon gas at a pressure of 2.5 atm is injected into a container at

25°C. What is the volume of the container?

Answer 1

The volume of container is 39.14 L.

Step-by-step explanation:

Given data:

Number of moles of neon = 4.0 mol

Pressure of gas = 2.5 atm

Temperature of gas = 25°C

Volume of container = ?

Solution:

we will use general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K

T = temperature in kelvin

Now we will convert the temperature.

25+273 = 298 K

Now we will put the values in formula.

2.5 atm × V = 4.0 mol × 0.0821 atm.L/ mol.K × 298 K

V = 97.86 atm.L /2.5 atm

V = 39.14 L

The volume of container is 39.14 L.