Question

What is an equation of the line that passes through the points (-6,5) and (6,7)

Answer 1

y = 1/6 x + 6

Explanation:

m = (y2-y1)/(x2-x1)

m = (7-5)/(6-(-6))

m = 2/12 = 1/6

Substitute x and y values with a pair of coordinates,

y = mx+c

7 = 1/6(6) + c

7 = 1 + c

c = 6

Thus, the equation is y = 1/6 x +6