Question

A 450.0 kg boat experiences two simultaneous forces. The motor exerts a force of 100.0 N to accelerate the boat forward, while an unknown drag force pushes in the opposite direction. The boat accelerates forward at 0.1330 m/s2. Calculate the drag force acting on the boat.

Answer 1

The drag force is
`D = 40.15 \ N`

Step-by-step explanation:

From the question we are told that

The mass is
`m = 450.0 \ kg`

The acceleration
`a  = 0.133 m/s^2`

The force due to the motor is
`F_m = 100 \ N`

Generally the net force acting on the boat is mathematically represented as

`F = m * a`

=>
`F = 450.0 * 0.1330`

=>
`F = 59.85 \ N`

Generally the drag force acting on the boat is mathematically represented as

`D = F_m -F`

=>
`D = 100 - 59.85`

=>
`D = 40.15 \ N`