Answer:
The water of the saturated clayed soil is 66.67 %.
Step-by-step explanation:
Given;
mass of saturated clayed soil,
= 600 g
mass of dry soil sample,
= 200 g
mass of water content,
=
-
= 600 g - 200 g = 400 g
The water content is determined as;
![M_w(\%) = (M_s - M_d)/(M_s) *100\%\\\\M_w(\%) = (600-200)/(600) *100 \% \\\\M_w(\%) = 66.67 \%](https://img.qammunity.org/2021/formulas/engineering/college/tebmqh1sernole7fmzt0lsv9kv7pn92qk2.png)
Therefore, the water of the saturated clayed soil is 66.67 %.