Answer:
Explanation:
The question is incomplete. Here is the complete question.
Find the (a) mean. (b) median. (c) mode, and (d) midrange for the given sample data. An experiment was conducted to determine whether a deficiency of carbon dioxide in the soil affects the phenotype of peas. Listed below are the phenotype codes where 1 = smooth-yellow, 2 = smooth-green, 3 = wrinkled-yellow, and 4= wrinkled-green. Do the results make sense?
Given the phenotype code as 4, 3, 3, 1, 3, 4, 1, 1, 1, 4, 2, 3, 1, 1
a) Mean is the average of the number. It is gotten by taking of the ratio of the variables to the sample size.
Sum of variables = 4+3+3+1+3+4+1+1+1+4+2+3+1+1
Sum of variables = 32
Sample size = 14
Mean = 32/14
Mean = 2.29
The mean phenotype is 2.29
B) median is the value at the middle after rearrangement either in ascendng or descending order.
On rearranging:
1,1,1,1,1,1),2,3,(3,3,3,4,4,4
It can be seen that there are two values at the middle. To get the actual median, we will take the median of the values.
Median = 2+3/2
Median = 5/2
Median = 2.5
Hecke the median phenotype is 2.5
c) The mode is the vale that is occurring the most in the data. It can be seen from the data that 1 is the only value occurring the most (6 times), hence the phenotype mode of the data is 1.
d) Midrange = Highest value + Lowest value/2
Midrange = 1+4/2
Midrange = 5/2
Mid range = 2.5
Hence the midrange of the phenotypic code is 2.5
e) Yes, the measures of center make sense since the data is numerical. Since all our values are numerical and measurable, hence we can conclude that the measure of centres make sense