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Choose all that give the correct expression for the quantity described. The difference of nine times a number x and the quotient of that number and 5. 9x − x 5 Eight more than the quotient of twelve and a number n. n 12 + 8 The product of a number and the quantity 'six minus the number' plus the quotient of eight and the number. x(6 − x) + 8 x Sum of three consecutive even integers. 2x + (2x + 2) + (2x + 4)

2 Answers

4 votes

Answer: 1st , 2nd, and 3rd!

Explanation:

User Tanny
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1 vote

Explanation:

We are to get the expression for the following statements;

1) The difference of nine times a number x and the quotient of that number and 5.

The product of nine and a number x is expressed as;


=9 * x\\= 9x

The quotient of that number and 5.


= (x)/(5)

The difference between both expression;


9x - (x)/(5)

Hence, the difference of nine times a number x and the quotient of that number and 5 is expressed as
9x - (x)/(5)

2) Eight more than the quotient of twelve and a number n

Quotient of twelve and a number n is expressed as:


(n)/(12)

Eight more than the resulting function is;


(n)/(12)+8

Hence eight more than the quotient of twelve and a number n is expressed as
(n)/(12)+8

3) The product of a number and the quantity 'six minus the number' plus the quotient of eight and the number.

Let the number be x:

six minus the number is expressed as;


6-x

product of a number x and the quantity 'six minus the number is;


x(6-x)

quotient of eight and the number is;


(8)/(x)

Taking the resulting sum of the last two expression


x(6-x) + 8x

Hence the product of a number and the quantity 'six minus the number' plus the quotient of eight and the number is expressed as;


x(6-x) + 8x

4) Sum of three consecutive even integers. 2x + (2x + 2) + (2x + 4).

Let the first even number be 2x

The consecutive even numbers are gotten by adding 2 to the preceding number. The two consecutive even integers are 2x+2 and 2x+2+2

the sum of three consecutive even integers is expressed as;


= 2x +(2x+2)+(2x+2+2)\\= 2x+(2x+2)+(2x+4)

User Gian Santillan
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