Question

Calculate the electrostatic force between a negatively charged PVC pipe (m = 300 g, q = -0.0000007 C) and a positively charged sweater (m = 650 g, q = 0.0000009 C) when they are held 6 cm apart (the centers of their charges are 6 cm apart). Your answer should include the magnitude of the force and clearly state whether they would be pushing or pulling each other with that amount force.

Answer 1

1.575 N

Step-by-step explanation:

Given that,

Charge on a PVC pipe, q₁ = -0.0000007 C

Charge on a positively charged sweater, q₂ = 0.0000009 C

Separation between charges, d = 6 cm = 0.06 m

We need to find the magnitude of the force between charges. The force between two charges is given by :

`F=(kq_1q_2)/(r^2)\\\\F=(9* 10^9* 0.0000007 * 0.0000009 )/((0.06)^2)\\\\F=1.575\ N`

So, the electrostatic force has a magnitude of 1.575 N.