Question

A car has initial velocity of 72 km/hr. It is accelerated at 2m/s2

Calculate the final velocity and distance covered after 3 sec.
What is the distance covered by a car in 3rd second?
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Answer 1

Vf=78

d=

Step-by-step explanation:

vf=vi+at

=72+(2)(3)

=78km/hr

d=vit+1/2at^2

=(72)(3)+1/2 (2)(3)^2

=216+9

=225m

Answer 2

• Answer:

1) 26m/s

2) 69 m

• Step-by-step explanation:

Hi there !

1)

a = (v₂ - v₁)/t => at = v₂ - v₁ => v₂ = at + v₁

v₁ = 72km/h = 72000m/3600s = 20m/s

v₂ = 2m/s²ₓ3s + 20m/s

= 6m/s + 20m/s

= 26 m/s

2)

d = v₁t + at²/2

= 20m/sₓ3s + 2m/s²ₓ9s²/2

= 60m + 9m

= 69 m

Good luck !