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Determine the sum of the terms in the series 25 + 30 + 35 + ⋯ + 245. Show your work.

User DovaX
by
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1 Answer

0 votes

Answer:

6075

Explanation:

  • Given series is: 25 + 30 + 35 + ⋯ + 245.

  • Here, first term (a) = 25
  • Common difference (d) = 5
  • Last term
    (a_n) = 245

  • First we find the number of terms that this series has by the following formula:


  • a_n = a+(n-1)d

  • Plugging the values of a, d and
    a_n, we find.


  • 245 = 25+(n-1)5


  • \implies 245 - 25=(n-1)5


  • \implies 220=(n-1)5


  • \implies (220)/(5)=n-1


  • \implies 44=n-1


  • \implies 44+1=n


  • \implies\red{\bold{ n=45}}

  • Thus, the given series contains 45 terms.

  • Next, we find the sum of the given series using the formula given below.


  • S_n = (n)/(2)(a+a_n)


  • \implies S_(45)= (45)/(2)(25+245)


  • \implies S_(45)= (45)/(2)(270)


  • \implies S_(45)=45*135


  • \implies\orange{\boxed{\boxed{\boxed{\bold{ S_(45)=6075}}}}}
User Yoav Epstein
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