Question

I need help on this!

Given the following right triangle △ ABC with m∠A = Θ°, find sin(Θ°) and cos(Θ°).

Answer 1

`\sf Sin \ \theta = (5)/(13)\\\\Cos \ \theta =(12)/(13)`

Explanation:

`\sf Sin \ \theta= (opposite \ of \ angle \ A)/(hypotenuse)\\\\`

`\sf =(BC)/(AB)\\\\ =(5)/(13)`

`\sf Cos \ \theta = (adjacent \ side \ of \ angle \ A)/(hypotenuse)\\`

`\sf =(AC)/(AB)\\\\= (12)/(13)`