Question

Select the four statements that are true. Select the four statements that are true.

Based on the equation for Hardy-Weinberg equilibrium, the expected number of wolves with the FBFB genotype is 40.
Based on the equation for Hardy-Weinberg equilibrium, the expected number of wolves with the FBFB genotype is 12.
Based on the equation for Hardy-Weinberg equilibrium, the expected number of wolves with the FBFW genotype is 40.
Based on the equation for Hardy-Weinberg equilibrium, the expected number of wolves with the FBFW genotype is 96.
The population is not at Hardy-Weinberg equilibrium. The population may be evolving because the actual number of individuals with each genotype differs from the expected number of individuals with each genotype.

Answer 1

Is this population in Hardy-Weinberg equilibrium?

✔ No

Which allele is increasing in the population?

✔ Allele C

Step-by-step explanation:

Edge 22

Answer 2

Answer: Based on the equation for Hardy-Weinberg equilibrium, the expected number of wolves with the FBFW genotype is 96.

Based on the equation for Hardy-Weinberg equilibrium, the expected number of wolves with the FBFB genotype is 12.

The population may be evolving because the actual number of individuals with each genotype differs from the expected number of individuals with each genotype.

The population is not at Hardy-Weinberg equilibrium.

Step-by-step explanation:

The FB allele should accounts for 120 of the alleles (40 × 2 = 80 in FBFB wolves, + 40 × 1 = 40 in FBFW wolves).

the FB allele would make up 20% (120/600) of the total alleles in the population, so the value of p would be 0.2. The allele frequencies of the population must add up to one for it to be valid (what this means is p+q=1); therefore, since the value of p is 0.2, and the value of q is 0.8.

According to the Hardy-Weinberg equation, the expected frequencies of the genotypes would add up to 1.

= p2+2pq+q2

= 1

or

= 0.22+2(0.2)(0.8)+0.82

= 1

or

= 0.04+0.32+0.64

= 1