Question

Can someone help with all 4 questions and show work on how to do all of them please

Answer 1

`\\ \rm\Rrightarrow |1/3(2^3-10^2/5)|=|1/3(8-20)|=|1/3(-12)|=4`

`\\ \rm\Rrightarrow |-(1/6)^3|=(1/6)^3=1/216`

`\\ \rm\Rrightarrow |6^3-7^3|=|216-343|=127`

`\\ \rm\Rrightarrow |9^2+(-9)^3|=|81-729|=648`

Answer 2

8) 1/216

13) 127

14) 648

15) 4

Explanation:

Question 8

`\large \begin{aligned}\displaystyle \left|-\left((1)/(6)\right)^3\right| & = \left|-\left((1^3)/(6^3)\right)\right|\\\\& = \left|-(1)/(216)\right|\\\\& = (1)/(216)\end{aligned}`

Question 13

`\large \begin{aligned}\displaystyle \left|6^3-7^3\right| & = \left|216-343\\ & = \left|-127\right|\\ & = 127\end{aligned}`

Question 14

`\large \begin{aligned}\displaystyle \left|9^2+(-9)^3\right| & = \left|81+(-729)\right|\\& = \left|81-729\right|\\& = \left|-648\right|\\& = 648\end{aligned}`

Question 15

`\large \begin{aligned}\displaystyle \left|(1)/(3)\left(2^3-(10^2)/(5)\right)\right| & = \left|(1)/(3)\left(8-(100)/(5)\right)\right|\\\\& = \left|(1)/(3)\left(8-20\right)\right|\\\\& = \left|(1)/(3)\left(-12\right)\right|\\\\& = \left|(-12)/(3)\right|\\\\& = \left|-4\right|\\\\& = 4\\\end{aligned}`