Question

HELLPPP

Solve the system by substitution.
-9x-10y=12
−3x+3=y

Answer 1

HELLPPP

Solve the system by substitution.
-9x-10y=12
−3x+3=y


X=2
Y= -3

Answer 2

`x=2\\y=-3`

Explanation:

We have:

`-9x-10y=12\\-3x+3=y`

Since we already have a variable value (
`y`) in the second equation, it would be easiest to substitute the value for
`y` in the first equation:

`-9x-10(-3x+3)=12`

Distribute
`-10` into
`(-3x+3)`:

`-9x+30x-30=12`

Combine like terms:

`21x-30=12`

Add
`30` to both sides of the equation:

`21x=42`

Divide by the coefficient of
`x`, which is
`21`:

`x=2`

_

Now that we have our
`x` value, we can substitute that in to the second equation to find our
`y` value:

`-3(2)+3=y`

Multiply:

`-6+3=y`

Combine like terms:

`-3=y`