Answer:
W = 13, L = 18.
Step-by-step explanation:
Given that Perimeter = 62ft and Area = 234ft
We have 2L + 2W = 62
2L = 62 - 2W
L = (62 - 2W) ÷ 2
L = 31 - W......(i)
LW= 234.....(ii)
Substitute equation (i) from (ii)
(31 - W) W = 234
31W - W² - 234 = 0
-W² + 31W - 234 = 0
W² - 31W + 234 = 0
(W - 18) (W - 13) = 0
W - 18 = 0
Hence, we have W=18 , L=13
Or
W -13 =0
W = 13, L = 18.
PROOF:
2 *18 + 2 * 13 = 62
36 + 39 = 62
62 = 62
And
13 * 18 = 234
234 = 234
Therefore, the final answer which is the dimensions of the school stage is Length 18ft and Width 13ft