Question

Write the equation of a line perpendicular to 6y-2x=-8 and passes through the point(-2,1) in slope-

intercept form

Answer 1

y = -3x + 17/10

Explanation:

First you want to move the 2x to the other side of the equal sign for the proper way of slope-intercept form. Which makes it 6y=2x-8.

You still want to make sure that y is by itself so you divide the whole equation by 6 which makes it y=1/3x-8/6.

We have to find the slope of the a perpendicular line now and to do so, you must take the slope of the given line and make it into the opposite reciprocal.

To do that you take 1/3 and reciprocate it, which makes it 3.

Then flip the sign to make it opposite. Like making a positive into a negative and a negative into a positive. Therefore the slope of the perpendicular line is -3.

Now we must make it past through point (-2,1). To do that you have to adjust the y-intercept. Because of that, the y-intercept is 1.7 or 17/10.

The equation of the slope is y=-3x+17/10