![\rule{50}{1}\large\blue\textsf{\textbf{\underline{Question:-}}}\rule{50}{1}](https://img.qammunity.org/2023/formulas/mathematics/high-school/ora0musxw6h9xk0xg3b8hxbi3egn6al9en.png)
What value of x makes the equation
true?
![\rule{50}{1}\large\blue\textsf{\textbf{\underline{Answer and how to solve:-}}}\rule{50}{1}](https://img.qammunity.org/2023/formulas/mathematics/high-school/fhar4n0mcy199h094mj2xtpgr501h0w0ef.png)
When solving an equation, we need to make sure that variables are on one side of the equation, which is usually the left-hand side, and numbers are on the other side, which is usually the right-hand side, of the equation.
Since we have variables on the right-hand side as well as the left-hand side, we need to move all of them to the left-hand side, with the opposite operation:-
Subtract 6x-3x:-
Now, divide by 3 on both sides:-
![\boxed{\boxed{\sf{x=6}}}\checkmark](https://img.qammunity.org/2023/formulas/mathematics/high-school/nc0lxm4l59zkilzp3gtvxp1k4r8vg6r56a.png)
We've found the value of x, but we also need to make sure our solution is correct.
We can do that by substituting 6 for x (into the original equation)
and seeing whether or not we have a true statement:-
![\implies\sf{6(6)=3(6)+18}](https://img.qammunity.org/2023/formulas/mathematics/high-school/jws06adei20yp95prmnq5gaxv34862y2rj.png)
![\implies\sf{36=18+18}](https://img.qammunity.org/2023/formulas/mathematics/high-school/izvwgg8v4r60h1r9f1hwyg4gj08vllfonz.png)
![\implies\sf{36=36}](https://img.qammunity.org/2023/formulas/mathematics/high-school/tpjogmyxyggzkpw79wr398ijvpkkwjgv8v.png)
Since the LHS equals the RHS, our solution (x=6) is correct.
Good luck with your studies.