Question

The length of a rectangle is 4 more than twice its width. If the perimeter of the

rectangle is 64 feet, find the dimensions of the rectangles

Answer 1

W=20
L=44

(2x+4)+x=64
-4 -4
———————
3x = 60
/3 /3
———————-
x = 20—>width

Length= 2 x width +4
2(20)+4=44