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HELP PLEASE!!!!!!!! 25 POINTS !!!1

HELP PLEASE!!!!!!!! 25 POINTS !!!1-example-1

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2 votes

Answer:

y = x² + 5x - 14

Step-by-step explanation:

If the zeros of a polynomial are 2 and -7, then:

⇒ x = 2 ⇒ (x - 2) = 0

⇒ x = -7 ⇒ (x + 7) = 0

Therefore, we can write the polynomial as:

y = a(x - 2)(x + 7) where a is some constant

As the first term of the given polynomial is x², we can say that its coefficient is 1. Therefore, a = 1

⇒ y = 1(x - 2)(x + 7)

⇒ y = (x - 2)(x + 7)

To write the polynomial in standard form ax² + bx + c

simply expand the brackets:

⇒ y = (x - 2)(x + 7)

⇒ y = x² + 7x - 2x - 14

⇒ y = x² + 5x - 14

User ProLoser
by
8.2k points
8 votes

Answer:


\sf x^2 + \boxed{\sf 5} \ x - \boxed{\sf 14}

Step-by-step explanation:

Given zero's of a polynomial function:

  • 2 and -7

Function's:

  • (x + 7) (x -2) = 0
  • x² + 7x - 2x - 14 = 0
  • x² + 5x - 14 = 0
User Eddy Pronk
by
9.6k points

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