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What are the intercepts of 7x+2y-14z=56
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What are the intercepts of 7x+2y-14z=56

What are the intercepts of 7x+2y-14z=56-example-1
User Chevan
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1 Answer

4 votes

Hey there!

I believe your answer should be: OPTION B. because


7x + 2y - 14z = 56

7(8) + 2(28) - 14(4) = 56

56 + 56 - 56 = 56

112 - 56 = 56

56 = 56


So, that’s why possibly Option B. could be your result


Good luck on your assignment & enjoy your day!



~Amphitrite1040:)

User Paranaaan
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