Question

A 0.4 kg aluminum part increases its temperature by 25°C. How much thermal energy is transferred to the part by heat? (specific heat of aluminum = 900 J/kg•°C) pleasssssssssseeeeeeeeeee help its on a testttt i need helppppp

Answer 1

`Q=9000J`

Step-by-step explanation:

Hello.

In this case, since the energy involved in a heating process is computed via:

`Q=mCp\Delta T`

Whereas m is the mass (0.4 kg), Cp is the specific heat (900 J/kg•°C) and ΔT the temperature rise (25 °C), the required heat turns out:

`Q=0.4kg*900(J)/(kg\°C)* 25\°C\\\\Q=9000J`

It means that 9000 J of energy is transferred to attain that temperature raise.

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