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5 votes
If 4 out of 7 armadillos

carry a defective gene,
about how many
armadillos carry the
normal gene in a
population of 843
armadillos? Round to the nearest whole.

1 Answer

2 votes

Answer:

About 231 armadillos

Explanation:

Step 1:

4 : 7 Ratio

Step 2:

4x + 7x = 843 Equation

Step 3:

11x = 843 Combine Like Terms

Step 4:

x = 843 ÷ 11 Divide

Step 5:

x ≈ 77

Step 6:

77 × 3 Multiply

Answer:

231

Hope This Helps :)

User Bethel
by
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