Question

What is an equation in slope intercept form of a line that passes through points (0,5) and (4,0)

Answer 1

y = -5/4x + 5

Explanation:

If you use rise/run it rises down 5 and runs to the right 4, therefore your slope is -5/4x and for your Y-intercept its 5 because (0,5) is already on the Y-axis, so your answer is y = -5/4x + 5

Answer 2

`m=(y_2-y_1)/(x_2-x_1)\\ m=(0-5)/(4-0) \\m=(-5)/(4) \\m=-(5)/(4)`

Therefore the slope is m = -5/4

Find the equation

Let
`y=mx+b` where m is slope and b is y-intercept.

Substitute m = -5/4 in the equation,

`y=-(5)/(4)x+b`

Substitute any ordered pairs that are given. I'll use (4,0) instead.

Substitute y = 0 and x = 4

`0=-(5)/(4)(4)+b\\ 0=-5+b\\5=b\\`

Thus, the y-intercept is 5 (b is 5)

Therefore, the equation is
`y=-(5)/(4)x+5` #