Question

Which is the equation of a line with a slope of -1/3 and a y-intercept at (0,1)?

Answer 1

2/3

Explanation:

Remember that when you want to write an EQUATION of the line with slope -1/3 and y-intercept (0,1), you can use the "Slope-intercept form" for the equation of the line.

The slope intercept form is: "y =mx+ b"

m is the slope, and b is the y-coordinate of the y-intercept.

For example, m =(-1/3) and b = (1)

Therefore, the equation of the line is

y = (-1/3) + 1

Put (-1/3) + 1 --> into the calculator and you get.....

2/3!!

Hope that helps!

Sydney

Answer 2

The answer is

`\huge \boxed{y = - (1)/(3)x + 1 }`

Explanation:

To find an equation of a line given the slope and a point we use the formula

`y - y_1 = m(x - x_1)`

where

m is the slope

( x1 , y1) is the point

From the question the point is (0,1) and slope - 1/3

The equation is

`y - 1 = - (1)/(3)(x - 0) \\ y - 1 = - (1)/(3) x`

We have the final answer as

`y = - (1)/(3) x + 1 \\`

Hope this helps you