Answer:
A) The critical value found is 5.99 which is < the test statistic value ( 6.94 ) hence we will reject the null hypothesis (H₀)
The P-value associated is : 0.031 which is < 0.05 ( level of significance )
B) from the calculation it can be sen that employees of small companies are more likely without health insurance
Explanation:
A) To conduct a test of independence
we apply the hypothesis test
Null hypothesis (H₀) = The health insurance coverage is independent of the size of the company
Alternative hypothesis (H₁) = The health insurance coverage is not independent of the size of the company
The test statistic is calculated as attached below
also the expected values are attached below indicating the formula used
E = expected value
O = observed value
Test statistic value ( as calculated ) = 6.94
The critical value found is 5.99 which is < the test statistic value ( 6.94 ) hence we will reject the null hypothesis (H₀)
The P-value associated is : 0.031 which is < 0.05 ( level of significance )
B) percentage of employees without health insurance
Small company : 14/50 * 100 = 28%
medium company: 10/75 * 100 = 13%
large company : 12/100 * 100 = 12%
from the above calculation it can be sen that employees of small companies are more likely without health insurance