Answer:
![(3)/(5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/8pel2zks03as2nk3mh2m6xy899gcr64l15.png)
Explanation:
Given that:
Total Number of fourth downs = 10
Number of fourth downs converted to first downs = 6
Formula for probability of an event E can be observed as:
![P(E) = \frac{\text{Number of favorable cases}}{\text {Total number of cases}}](https://img.qammunity.org/2021/formulas/mathematics/high-school/aeg3h4h3bbx73banosb6zhsdb88ck3qbng.png)
Here, Let E be the event of getting a fourth down converted to first down.
So, Number of favorable cases = 6
Total Number of cases = 10
Therefore, the required probability is:
![P(E) = (6)/(10) = (3)/(5)](https://img.qammunity.org/2021/formulas/mathematics/high-school/ijuwkgjk7kszfhlxtwlz7nal1lm5sjdj7p.png)