Question

Solve the quadratic using the quadratic formula. *
Solve:
6x^2 + 7x – 5 = 0

Answer 1

`x=(1)/(2)`

`x=-1(2)/(3)`

Explanation:

`x=\frac{-b±\sqrt{b^(2) +4ac} }{2a}`

Ignore the A before the ±, it wouldn't let me type it correctly.

6x² + 7x - 5 = 0

a = 6

b = 7

c = - 7

`x=\frac{-(7)±\sqrt{7^(2) +4((6)(-5))} }{2(6)}`

`x=(-(7)±√(49 +4((6)(-5))) )/(2(6))`

`x=(-(7)±√(49 +120) )/(2(6))`

`x=(-7±√(169) )/(12)`

`x=(-7±13 )/(12)`

Two separate equations

`x=(-7+13 )/(12)`

`x=(-7-13 )/(12)`

________________________

`x=(-7+13 )/(12)`

`x=(6 )/(12)`

`x=(1)/(2)`

`x=(-7-13 )/(12)`

`x=(-20 )/(12)`

`x=-1(2)/(3)`

Answer 2

Answer:x = -5/3 or x = 1/2

Explanation:

Let's solve your equation step-by-step.

6x2+7x−5=0

Step 1: Factor left side of equation.

(3x+5)(2x−1)=0

Step 2: Set factors equal to 0.

3x+5 = 0 or 2x−1 = 0

x = -5/3 or x = 1/2