Answer:
The answer is below
Step-by-step explanation:
If one machine breaks, the others breaks, this means that the are connected in series, hence the reliability of the line is:
Reliability of line = 0.92 * 0.97 * 0.87 = 0.7764
A) Plan 1: Plan A involves connecting a backup line in parallel, therefore the overall reliability would be:
Overall reliability = 1 - (1 - 0.7764)² = 0.95
B) Plan 2: In plan B, each machine has a backup.
Hence:
For machine A: Reliability = 1 - (1 - 0.92)² = 0.9936
For machine B: Reliability = 1 - (1 - 0.97)² = 0.9991
For machine C: Reliability = 1 - (1 - 0.97)² = 0.9831
Overall system reliability = 0.9936*0.9991*0.9831 = 0.9759
C) Since plan 2 has a higher reliability hence plan 2 is the better plan