Answer:
X = 10
Step-by-step explanation:
First, we need to calculate the moles of Na₂CO₃ in the 0.948g. Then, the moles of water based on the difference of masses. X will be the ratio of moles of water and moles of sodium carbonate.
Moles Na₂CO₃ (Molar mass: 105.99g/mol):
0.948g * (1mol / 105.99g) = 8.944x10⁻³ moles
Moles H₂O (Molar mass: 18.02g/mol):
2.558g - 0.948g = 1.61g of water
1.61g * (1mol / 18.02g) =0.08935 moles
The ratio, X, is:
0.08935mol / 8.944x10⁻³ moles
X = 10