Answer:
The null hypothesis will not be rejected.
Explanation:
The hypothesis for the test is:
H₀: There is no difference between the two population means, i.e. d = 0.
Hₐ: There is a significant difference between the two population means, i.e. d ≠ 0.
Consider the Excel output attached.
The mean of the differences is,
.
The standard deviation of the differences is,
.
Compute the test statistic as follows:

The degrees of freedom is, n - 1 = 7.
Compute the p-value as follows:

The decision rule is:
The null hypothesis will be rejected if the p-value of the test is less than the significance level.
p-value = 0.112 > α = 0.02.
The null hypothesis will not be rejected.