Question

Write a quadratic function in standard form with zeros 1 and -10 plzzzz helppp meee

Answer 1

`f(x)=x^2+9x-10`

Explanation:

Standard Form of Quadratic Function

The standard representation of a quadratic function is:

`f(x)=ax^2+bx+c`

where a,b, and c are constants.

The factored form of a quadratic equation is:

`f(x)=a(x-\alpha)(x-\beta)`

Where
`\alpha` and
`\beta` are the roots or zeros of f.

The question gives the zeros of the function: 1 and -10. This makes our function look like:

`f(x)=a(x-1)[x-(-10)]`

`f(x)=a(x-1)(x+10)`

Operating:

`f(x)=a(x^2+10x-x-10)`

Joining like terms:

`f(x)=a(x^2+9x-10)`

Since we are not given any more conditions, we choose the value of a=1, thus. the required function is:

`\boxed{f(x)=x^2+9x-10}`