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20 votes
Solve the system of the linear equations with three variables:

6x + 4y + z = 12
6x + 4y + 2z = 12
6x + 4y + 3z = 12

User King Holly
by
6.0k points

1 Answer

11 votes

Answer:

z = 0

y = -3x/2 + 3

Explanation:

6x + 4y + z = 12

6x + 4y + 2z = 12

6x + 4y + 3z = 12

Second equation minus first equation:

z = 0

If you plug in z = 0 in all the original equations, you get a single equation:

3x + 2y = 6

The best you can do is to solve for y in terms of x.

y = -3x/2 + 3

Answer:

z = 0

y = -3x/2 + 3

User Chris DeSalvo
by
7.4k points
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