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Line PQ is located in the coordinate plane with point P at(-2,-2)

and point Q at (0,7). Point R is located at (3, 0). For what coordinates of point S will lines PQ and RS be parallel?
(5,9)
(9,5)
(5. – 1)
(1-1,5)

Line PQ is located in the coordinate plane with point P at(-2,-2) and point Q at (0,7). Point-example-1
User Lempkin
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1 Answer

3 votes

Answer:

The coordinates of point S are (5, 9) will make line PQ // line RS ⇒ A

Explanation:

Parallel lines have the same slopes

The slope of a line = Δy/Δx, where

  • Δ y is the change of y
  • Δ x the change of x

Let us first find the slope of the line PQ.

P = (-2, -2) and Q = (0, 7)

Δx = 0 - (-2) = 0 + 2 = 2

Δy = 7 - (-2) = 7 + 2 = 9

The slope of PQ = 9/2

∵ Line PQ // line RS

∴ The slope of line PQ = the slope of line RS

The slope of line RS =9/2

Point R = (3, 0) and point S = (x, y)

∵ The slope of line RS = 9/2

∵ The slope = Δy/Δx

∴ Δy/Δx = 9/2

→ That means Δy = 9 and Δx = 2

Δy = y - 0

∵ Δy = 9

9 = y

Δx = x - 3

∵ Δx = 2

∴ 2 = x - 3

→ Add 3 to both sides

∴ 2 + 3 = x - 3 + 3

5 = x

The coordinates of point S are (5, 9) will make line PQ // line RS

User Pouya Zad
by
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