Question

A. In the complete reaction of 22.99 g of sodium

with 35.45 g of chlorine, what mass of sodium
chloride is formed?

Answer 1

Answer : 58.44 g

Further explanation

The reaction

`\tt Na+Cl\Rightarrow NaCl`

mole ratio :

Na : Cl : NaCl = 1 : 1 : 1

Molar mass of Na : 22,989769 g/mol = 22.99 g/mol

Molar mass of Cl : 35,453 g/mol= 35.45 g/mol

Molar mass of NaCl : 58,44 g/mol

Let's check the mol for reactant (Na and Cl) and product(NaCl)

• mol of Na :

`\tt mol=(22.99)/(22.99)=1`

• mol of Cl :

`\tt mol=(35.45)/(35.45)=1`

Then the reactants are completed reacting because it matches the mole ratio, which is 1: 1

so that the mole of the product can be determined from the mol Na or Cl, which is 1

• mass of NaCl :

`\tt =(mol~NaCl)/(mol~Na)* MW~NaCl\\\\=(1)/(1)* 58.44\\\\=\boxed{\bold{58.44~g}}`