Question

If the volume of oxygen gas is 259 cm3 at 112 kPa, what would the volume be at 101.3 kPa?

Answer 1

The answer is 286.36 cm³

Step-by-step explanation:

In order to find the volume be at 101.3 kPa we use Boyle's law which is

`P_1V_1 = P_2V_2`

where

P1 is the initial pressure

P2 is the final pressure

V1 is the initial volume

V2 is the final volume

Since we are finding the final volume

`V_2 = (P_1V_1)/(P_2) \\`

From the question

P1 = 112 kPa = 112000 Pa

V1 = 259 cm³

P2 = 101.3 kPa = 101300 Pa

We have

`V_2 = (112000 * 259)/(101300) = (29008000)/(101300) \\ = 286.3573543...`

We have the final answer as

286.36 cm³

Hope this helps you