Answer:
Jason has $58.20 and Jeff has $13.80.
Explanation:
Let x represent the amount of money Jason has, and y represent the amount of money Jeff has.
We know that together they have $72. So, we can write the following equation:
![x+y=72](https://img.qammunity.org/2021/formulas/mathematics/middle-school/4ta5qjq6ruwbj1ydvyjvrszs279q4ficnm.png)
We know that Jason has three more than four times the amount of money Jeff has. So:
![x=3+4y](https://img.qammunity.org/2021/formulas/mathematics/high-school/zjsyoilv8jgm4zxoghih4w5m4w5njr64x2.png)
This is a system of equations. We can solve it by using substitution. Let's substitute the second equation into the first. This yields:
![(3+4y)+y=72](https://img.qammunity.org/2021/formulas/mathematics/high-school/plnb1edpoamfiv1evpfcyy9bs63hjielsv.png)
Combine like terms:
![5y+3=72](https://img.qammunity.org/2021/formulas/mathematics/high-school/z5n37kyjz7w5bztu8w1kodvakzj8gmzupb.png)
Subtract 3 from both sides:
![5y=69](https://img.qammunity.org/2021/formulas/mathematics/high-school/b7x6huq6upfs9rt1fji5b7r2zvodnt3xz2.png)
Divide both sides by 5:
![y=69/5=\$13.80](https://img.qammunity.org/2021/formulas/mathematics/high-school/3xgk7ivbybin1tjwzx1r6kht83masmtz4r.png)
So, Jeff has $13.80
We know that Jason has three more than four times the amount of money Jeff has.
Therefore, Jason has:
![x=13.8(4)+3](https://img.qammunity.org/2021/formulas/mathematics/high-school/1qhj4a41fzwzwrdnvq3obrtt96uo0bkw07.png)
Multiply and add:
![x=\$58.20](https://img.qammunity.org/2021/formulas/mathematics/high-school/pkfcn3aevx971enkpkg2tk7fj3we6z9hn7.png)
So, Jason has $58.20 and Jeff has $13.80.
And we're done!